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Add default known_only to parse_flags_with_usage #120

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Add default known_only to parse_flags_with_usage #120

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6 changes: 4 additions & 2 deletions absl/app.py
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Original file line number Diff line number Diff line change
Expand Up @@ -143,19 +143,21 @@ def parse(self, arg):
sys.exit(1)


def parse_flags_with_usage(args):
def parse_flags_with_usage(args, known_only=False):
"""Tries to parse the flags, print usage, and exit if unparseable.

Args:
args: [str], a non-empty list of the command line arguments including
program name.
known_only: bool, if True, parse and remove known flags; return the rest
untouched. Unknown flags specified by --undefok are not returned.

Returns:
[str], a non-empty list of remaining command line arguments after parsing
flags, including program name.
"""
try:
return FLAGS(args)
return FLAGS(args, known_only=known_only)
except flags.Error as error:
sys.stderr.write('FATAL Flags parsing error: %s\n' % error)
sys.stderr.write('Pass --helpshort or --helpfull to see help on flags.\n')
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