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Allow types to determine how to decode themselves #287

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11 changes: 11 additions & 0 deletions mapstructure.go
Original file line number Diff line number Diff line change
Expand Up @@ -453,6 +453,13 @@ func (d *Decoder) decode(name string, input interface{}, outVal reflect.Value) e
return nil
}

if outVal.CanAddr() {
v := outVal.Addr()
if u, ok := v.Interface().(decoder); ok {
return u.Decode(input)
}
}

if d.config.DecodeHook != nil {
// We have a DecodeHook, so let's pre-process the input.
var err error
Expand Down Expand Up @@ -1540,3 +1547,7 @@ func dereferencePtrToStructIfNeeded(v reflect.Value, tagName string) reflect.Val
}
return v
}

type decoder interface {
Decode(interface{}) error
}
29 changes: 29 additions & 0 deletions mapstructure_examples_test.go
Original file line number Diff line number Diff line change
Expand Up @@ -254,3 +254,32 @@ func ExampleDecode_omitempty() {
// Output:
// &map[Age:0 FirstName:Somebody]
}

type Someone struct {
Name string
}

func (p *Someone) Decode(v interface{}) error {
if name, ok := v.(string); ok {
p.Name = name
return nil
}
return fmt.Errorf("undecipherable name")
}

func ExampleDecode_custom_decoder_type() {
type Profile struct {
Friends []Someone
}
input := map[string]interface{}{
"friends": []string{"Mitchell"},
}
var result Profile
err := Decode(input, &result)
if err != nil {
panic(err)
}
fmt.Printf("%#v", result)
// Output:
// mapstructure.Profile{Friends:[]mapstructure.Someone{mapstructure.Someone{Name:"Mitchell"}}}
}