TypeError: Server.emit() got an unexpected keyword argument 'broadcast'

[RDaneelOlivav]

Bug report

TypeError: Server.emit() got an unexpected keyword argument 'broadcast'

Required information:

• Operating system and version: Ubuntu 22
• OpenRMF installation type:
  debians
• OpenRMF version or commit hash
  debians
• ROS distribution and version:
  humble
• ROS installation type:
  by debians

Description of the bug

When launching the any example that launches the rmf comons, gives this error:

TypeError: Server.emit() got an unexpected keyword argument 'broadcast'

This makes the web interface not work.

I tracked the error until here:

simple_api_server.py

Is there a version that I'm not aware of?

How to reproduce

execute:

ros2 launch rmf_demos_gz_classic hotel.launch.xml | grep "Server.emit"

You should see that error.

Expected behavior

I would imagine that following this tutorial of installation, there shouldn't be any errors:
open-rmf/rmf#267

Screenshots

Additional information

I will try to do the same but installing rmf from source but I really don't understand why this could be happening. Hve I done something wrong in the installation?

UPDATE: Did the source installation with the exact same results
UPDATE2: Tried to update the Websockets, like so ISSUE, same result.

[RDaneelOlivav]

Not solved, but seems at least not affects the assignments of tasks and so on.
Although it continues to not show the tasks in the web interface ( the old one ) . So I imagen I'll close the issue

[YYZ252]

I had the same problem and finally solved it by follow the guide of "#169".

sudo apt remove python3-websockets 
python3 -m pip install websockets==10.4
python3 -m pip install asyncio